230.二叉搜索树中第k小的元素
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @param {number} k
* @return {number}
*/
var kthSmallest = function(root, k) {
let stack=[]
let node=root
while(node||stack.length){
while(node){
stack.push(node)
node=node.left
}
node=stack.pop()
if(--k==0){
return node.val
}
node=node.right
}
return false
};
采用中序遍历 找到第k个值
标签:node,right,return,val,树中,二叉,230,stack,left From: https://www.cnblogs.com/KooTeam/p/18578487