Implement the type version of Lodash.uniq, Unique takes an Array T, returns the Array T without repeated values.
type Res = Unique<[1, 1, 2, 2, 3, 3]>; // expected to be [1, 2, 3]
type Res1 = Unique<[1, 2, 3, 4, 4, 5, 6, 7]>; // expected to be [1, 2, 3, 4, 5, 6, 7]
type Res2 = Unique<[1, "a", 2, "b", 2, "a"]>; // expected to be [1, "a", 2, "b"]
type Res3 = Unique<[string, number, 1, "a", 1, string, 2, "b", 2, number]>; // expected to be [string, number, 1, "a", 2, "b"]
type Res4 = Unique<[unknown, unknown, any, any, never, never]>; // expected to be [unknown, any, never]
/* _____________ Your Code Here _____________ */
export type Equal<T, U> =
(<P>(x: P) => P extends T ? 1: 2) extends
(<P>(x: P) => P extends U ? 1: 2)
? true
: false;
export type IndexOf<T extends any[], U, ACC extends unknown[] = []> = T extends [infer F, ...infer RT]
? Equal<F, U> extends true
? ACC['length']
: IndexOf<RT, U, [...ACC, unknown]>
: -1;
export type Unique<T extends any[], ACC extends any[] = []> = T extends [infer F, ...infer RT]
? IndexOf<ACC, F> extends -1
? Unique<RT, [...ACC, F]>
: Unique<RT, ACC>
: ACC;
/* _____________ Test Cases _____________ */
import type { Equal, Expect } from '@type-challenges/utils'
type cases = [
Expect<Equal<Unique<[1, 1, 2, 2, 3, 3]>, [1, 2, 3]>>,
Expect<Equal<Unique<[1, 2, 3, 4, 4, 5, 6, 7]>, [1, 2, 3, 4, 5, 6, 7]>>,
Expect<Equal<Unique<[1, 'a', 2, 'b', 2, 'a']>, [1, 'a', 2, 'b']>>,
Expect<Equal<Unique<[string, number, 1, 'a', 1, string, 2, 'b', 2, number]>, [string, number, 1, 'a', 2, 'b']>>,
Expect<Equal<Unique<[unknown, unknown, any, any, never, never]>, [unknown, any, never]>>,
]
标签:Typescript,_____________,Unqiue,Medium,extends,Expect,expected,Unique,type From: https://www.cnblogs.com/Answer1215/p/16838974.html