Implement the type version of Lodash.without, Without<T, U> takes an Array T, number or array U and returns an Array without the elements of U.
type Res = Without<[1, 2], 1>; // expected to be [2]
type Res1 = Without<[1, 2, 4, 1, 5], [1, 2]>; // expected to be [4, 5]
type Res2 = Without<[2, 3, 2, 3, 2, 3, 2, 3], [2, 3]>; // expected to be []
/* _____________ Your Code Here _____________ */
type Without<T extends any[], U extends any[] | any> = T extends [infer F, ...infer RT]
? U extends any[] // U is array like
? F extends U[number] // F in U array
? Without<RT, U> // exlcude F
: [F, ...Without<RT, U>] // include F
: F extends U // U is not an array like
? Without<RT, U> // exlcude F
: [F, ...Without<RT, U>] // include F
: [];
/* _____________ Test Cases _____________ */
import type { Equal, Expect } from '@type-challenges/utils'
type cases = [
Expect<Equal<Without<[1, 2], 1>, [2]>>,
Expect<Equal<Without<[1, 2, 4, 1, 5], [1, 2]>, [4, 5]>>,
Expect<Equal<Without<[2, 3, 2, 3, 2, 3, 2, 3], [2, 3]>, []>>,
]
标签:Typescript,_____________,Medium,extends,Expect,array,type,Without From: https://www.cnblogs.com/Answer1215/p/16830018.html