1 class Solution { 2 public: 3 int maxTotalReward(vector<int>& rewardValues) { 4 int m = ranges::max(rewardValues); 5 unordered_set<int> s; 6 for (int v : rewardValues) { 7 if (s.contains(v)) { 8 continue; 9 } 10 if (v == m - 1 || s.contains(m - 1 - v)) { 11 return m * 2 - 1; 12 } 13 s.insert(v); 14 } 15 16 ranges::sort(rewardValues); 17 rewardValues.erase(unique(rewardValues.begin(), rewardValues.end()), rewardValues.end()); 18 19 bitset<100000> f{1}; 20 for (int v : rewardValues) { 21 int shift = f.size() - v; 22 f |= f << shift >> (shift - v); 23 } 24 for (int i = m * 2 - 1;; i--) { 25 if (f.test(i)) { 26 return i; 27 } 28 } 29 } 30 };
标签:end,int,contains,II,rewardValues,3181,return,LeetCode From: https://www.cnblogs.com/greenofyu/p/18503913