题目链接:https://www.luogu.com.cn/problem/P3850
主要操作就是:插入 + 查询第 k 值。
示例程序:
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1.1e5 + 5, maxb = 20;
struct Node {
int s[2], p, sz;
string name;
Node() {}
Node(string _name, int _p) { s[0] = s[1] = 0; p = _p; sz = 1; name = _name; }
} tr[maxn];
int root, idx;
void push_up(int x) {
auto &u = tr[x], &l = tr[u.s[0]], &r = tr[u.s[1]];
u.sz = l.sz + 1 + r.sz;
}
void f_s(int p, int u, int k) {
tr[p].s[k] = u;
tr[u].p = p;
}
void rot(int x) {
int y = tr[x].p, z = tr[y].p;
int k = tr[y].s[1] == x;
f_s(z, x, tr[z].s[1] == y);
f_s(y, tr[x].s[k^1], k);
f_s(x, y, k^1);
push_up(y), push_up(x);
}
void splay(int x, int k) {
while (tr[x].p != k) {
int y = tr[x].p, z = tr[y].p;
if (z != k)
(tr[y].s[1]==x)^(tr[z].s[1]==y) ? rot(x) : rot(y);
rot(x);
}
if (!k) root = x;
}
int n, m, q;
string book[202];
char ch[maxb];
int build(int l, int r, int p) {
if (l > r) return 0;
int mid = (l + r) / 2, x = mid;
tr[x] = Node(book[mid], p);
tr[x].s[0] = build(l, mid-1, x);
tr[x].s[1] = build(mid+1, r, x);
push_up(x);
if (l == 1 && r == n) root = x;
return x;
}
int get_k(int k) {
int u = root;
while (u) {
if (tr[tr[u].s[0]].sz >= k) u = tr[u].s[0];
else if (tr[tr[u].s[0]].sz + 1 == k) return u;
else k -= tr[tr[u].s[0]].sz + 1, u = tr[u].s[1];
}
return -1;
}
void init() {
tr[0].s[0] = tr[0].s[1] = tr[0].p = tr[0].sz = 0;
}
int cnt;
string ans[maxn];
void dfs(int u) {
if (!u) return;
dfs(tr[u].s[0]);
ans[cnt++] = tr[u].name;
dfs(tr[u].s[1]);
}
int main() {
init();
scanf("%d", &n);
for (int i = 1; i <= n; i++)
cin >> book[i];
build(1, n, 0);
root = (1 + n) / 2;
idx = n;
scanf("%d", &m);
for (int i = 0; i < m; i++) {
assert(tr[root].sz == n + i);
int k;
scanf("%s%d", ch, &k);
string s = ch;
if (k == 0) {
int y = get_k(1);
splay(y, 0);
assert(!tr[y].s[0]);
tr[++idx] = Node(s, y);
tr[y].s[0] = idx;
push_up(y);
}
else {
int y = get_k(k);
splay(y, 0);
int z = tr[y].s[1];
if (!z) {
assert(!tr[y].s[1]);
tr[++idx] = Node(s, y);
tr[y].s[1] = idx;
push_up(y);
}
else {
while (tr[z].s[0]) z = tr[z].s[0];
splay(z, y);
assert(tr[y].s[1] == z && tr[y].s[1] == z);
assert(!tr[z].s[0]);
tr[++idx] = Node(s, z);
tr[z].s[0] = idx;
push_up(z), push_up(y);
assert(y == root);
}
}
}
dfs(root);
scanf("%d", &q);
while (q--) {
int x;
scanf("%d", &x);
printf("%s\n", ans[x].c_str());
}
return 0;
}
标签:sz,洛谷,idx,P3850,int,tree,tr,up,root
From: https://www.cnblogs.com/quanjun/p/18493438