#include <stdio.h>
int main(void)
{
int n;
int i = 0;
while (scanf("%d",&n) != EOF)
{
int former[100000] = { 1 };
int later[100000] = { 0 };
if (n > 2 && n % 2 == 0)
{
printf("Yes");
}
else
{
for (int x = 0; x < (n / 2) + 1; x++)
{
later[x] = n - former[x];
former[x] = x + 1;
}
for (int y = 0; y< n; y++)
{
if (later[y] % 2 == 0 && former[y] % 2 == 0)
{
for (int z = 0; z < n; z++)
{
if (later[z] % 2 == 1 && former[z] % 2 == 1)
{
printf("Yes");
break;
}
}
break;
}
else
{
printf("No");
break;
}
}
}
printf("\n");
i++;
if (i == 10000)
break;
}
return 0;
}1.循环嵌套循环时注意及时跳出
2.注意奇偶讨论
标签：奇偶,int,later,break,++,printf,former From： https://blog.csdn.net/ROBIN__dyc/article/details/142863637