任务1:
源代码:
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <time.h> 4 5 #define N 5 6 #define N1 397 7 #define N2 476 8 #define N3 21 9 10 int main() { 11 int cnt; 12 int random_major, random_no; 13 14 srand(time(NULL)); // 以当前系统时间作为随机种子 15 16 cnt = 0; 17 while(cnt < N) { 18 random_major = rand() % 2; 19 20 if(random_major) { 21 random_no = rand() % (N2 - N1 + 1) + N1; 22 printf("20248329%04d\n", random_no); 23 } 24 else { 25 random_no = rand() % N3 + 1; 26 printf("20248395%04d\n", random_no); 27 } 28 29 cnt++; 30 } 31 32 return 0; 33 }
运行结果:
回答问题:
(1)line21代码 random_no = rand() % (N2 - N1 + 1) + N1; 的功能:
生成一个在区间 [N1, N2]
内的随机数
(2)line25代码 random_no = rand() % N3 + 1; 的功能:
生成一个在区间[1, N3]
内的随机数
(3)这个程序的功能是什么:
生成一定数量的随机编号并输出
任务2
源代码:
1 // 一元二次方程求解 2 3 #include <stdio.h> 4 #include <math.h> 5 6 int main() { 7 double a, b, c; 8 double delta, p1, p2; // 用于保存中间计算结果 9 10 while(scanf("%lf%lf%lf", &a, &b, &c) != EOF) { 11 if(a == 0) { 12 printf("a = 0, invalid input\n"); 13 continue; 14 } 15 16 delta = b*b - 4*a*c; 17 p1 = -b/2/a; 18 p2 = sqrt(fabs(delta))/2/a; 19 20 if(delta == 0) 21 printf("x1 = x2 = %.2g\n", p1); 22 else if(delta > 0) 23 printf("x1 = %.2g, x2 = %.2g\n", p1+p2, p1-p2); 24 else { 25 printf("x1 = %.2g + %.2gi, ", p1, p2); 26 printf("x2 = %.2g - %.2gi\n", p1, p2); 27 } 28 } 29 30 return 0; 31 }
运行结果:
任务3
源代码:
1 #include <stdio.h> 2 3 int main() { 4 char signal; 5 while (scanf(" %c", &signal)!= EOF) { 6 if (signal == 'r') { 7 printf("stop!\n"); 8 } else if (signal == 'g') { 9 printf("go go go\n"); 10 } else if (signal == 'y') { 11 printf("wait a minute\n"); 12 } else { 13 printf("something must be wrong...\n"); 14 } 15 } 16 return 0; 17 }
运行结果:
任务4
源代码:
1 #include <stdio.h> 2 3 int main() { 4 double expense; 5 double max = 0.0; 6 double min = 20000.0; 7 double totalExpense = 0.0; 8 printf("输入今日开销,直到输入-1终止: "); 9 while (scanf("%lf", &expense)!= EOF && expense!= -1) { 10 if (expense > max) { 11 max = expense; 12 } 13 if (expense < min) { 14 min = expense; 15 } 16 totalExpense += expense; 17 } 18 if (max > 0 && min < 20000 && totalExpense > 0) { 19 printf("今日最高一笔开销: %.1lf\n", max); 20 printf("今日最低一笔开销: %.1lf\n", min); 21 printf("今日累计消费总额: %.1lf\n", totalExpense); 22 } else { 23 printf("error.\n"); 24 } 25 return 0; 26 }
运行结果:
任务5
源代码:
1 #include <stdio.h> 2 3 int main() { 4 int a, b, c; 5 while (scanf("%d %d %d", &a, &b, &c)!= EOF) { 6 if (a + b <= c || a + c <= b || b + c <= a) { 7 printf("不能构成三角形\n"); 8 } else { 9 if (a == b && b == c) { 10 printf("等边三角形\n"); 11 } else if (a == b || a == c || b == c) { 12 if (a * a + b * b == c * c || a * a + c * c == b * b || b * b + c * c == a * a) { 13 printf("等腰直角三角形\n"); 14 } else { 15 printf("等腰三角形\n"); 16 } 17 } else if (a * a + b * b == c * c || a * a + c * c == b * b || b * b + c * c == a * a) { 18 printf("直角三角形\n"); 19 } else { 20 printf("普通三角形\n"); 21 } 22 } 23 } 24 return 0; 25 }
运行结果:
任务6
源代码:
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <time.h> 4 5 int main() { 6 srand(time(NULL)); 7 int luckyDay = rand() % 30 + 1; 8 int guess; 9 int chances = 3; 10 printf("猜猜2024年11月哪一天会是你的lucky day\n 开始喽,你有三次机会,猜吧( 1 and 30):\n"); 11 while (chances > 0) { 12 scanf("%d", &guess); 13 if (guess == luckyDay) { 14 printf("You guessed it right!\n"); 15 return 0; 16 } else if (guess < luckyDay) { 17 printf("你猜的日期早了,你的lucky day还没到呢\n"); 18 } else { 19 printf("你猜的日期晚了,你的lucky day在前面哦\n"); 20 } 21 chances--; 22 } 23 printf("次数用光啦。偷偷告诉你,11月你的lucky day是%d.\n", luckyDay); 24 return 0; 25 }
运行结果:
标签:%.,int,random,else,实验,printf,include From: https://www.cnblogs.com/tzrblogs/p/18454743