打印
systemtap的embedded C中,不能#include <stdio.h>,也不能用printf和print。那怎么打印呢?用STAP_PRINTF。用法与printf一样。
还可以访问cript中的全局变量。
官方文档中的示例:
global var
global var2[100]
function increment() %{
/* pragma:read:var */ /* pragma:write:var */
/* pragma:read:var2 */ /* pragma:write:var2 */
STAP_GLOBAL_SET_var(STAP_GLOBAL_GET_var()+1); //var++
STAP_GLOBAL_SET_var2(1, 1, STAP_GLOBAL_GET_var2(1, 1)+1); //var2[1,1]++
%}
注意function中头两行的注释不能删。具体意义看文档。
返回
获取一个task_struct的sibling的函数这样写:
function GetSibling(task:long) %{
struct task_struct *task = (struct task_struct*)STAP_ARG_task;
return list_entry(task->sibling.next, struct task_struct, sibling);
%}
报错:
include/linux/kernel.h:908:41: 错误:expected ‘;’ before ‘(’ token
#define container_of(ptr, type, member) ({ \
^
include/linux/list.h:374:2: 附注:in expansion of macro ‘container_of’
container_of(ptr, type, member)
^
/tmp/stapcGCPg6/stap_8142d625ec4d0f2acc7a14543f578111_12083_src.c:1416:9: 附注:in expansion of macro ‘list_entry’
return list_entry(task->sibling.next, struct task_struct, sibling);
^
/tmp/stapcGCPg6/stap_8142d625ec4d0f2acc7a14543f578111_12083_src.c: 在文件作用域:
cc1: 错误:无法识别的命令行选项“-Wno-tautological-compare” [-Werror]
看起来好像是编译器出错了。
但是原因其实是embedded C不能写return,要写STAP_RETURN。
所以要改成这样:
function GetSibling(task:long) %{
struct task_struct *task = (struct task_struct*)STAP_ARG_task;
STAP_RETURN(list_entry(task->sibling.next, struct task_struct, sibling));
%}
打印路径
可以用d_path把struct path解析为绝对路径。centos 7中d_path的声明如下:
// include/linux/dcache.h
extern char *d_path(const struct path *, char *, int);
其中char*是buffer的首地址,int是buffer的大小。
注意,d_path的返回值并不是传进去的buffer。直接输出buffer会输出空串。。。
正确用法示例:
static char full_path[BUFFER_SIZE];
STAP_PRINTF("%s\n", d_path(&(f->f_path), full_path, BUFFER_SIZE));
错误用法示例:
static char full_path[BUFFER_SIZE];
d_path(&(f->f_path), full_path, BUFFER_SIZE);
STAP_PRINTF("%s\n", full_path);
标签:task,struct,embedded,var2,STAP,笔记,sibling,systemtap,path
From: https://www.cnblogs.com/searchstar/p/18437900