Minimum Index Sum of Two Lists
Given two arrays of strings list1 and list2, find the common strings with the least index sum.
A common string is a string that appeared in both list1 and list2.
A common string with the least index sum is a common string such that if it appeared at list1[i] and list2[j] then i + j should be the minimum value among all the other common strings.
Return all the common strings with the least index sum. Return the answer in any order.
Example 1:
Input: list1 = ["Shogun","Tapioca Express","Burger King","KFC"], list2 = ["Piatti","The Grill at Torrey Pines","Hungry Hunter Steakhouse","Shogun"]
Output: ["Shogun"]
Explanation: The only common string is "Shogun".
Example 2:
Input: list1 = ["Shogun","Tapioca Express","Burger King","KFC"], list2 = ["KFC","Shogun","Burger King"]
Output: ["Shogun"]
Explanation: The common string with the least index sum is "Shogun" with index sum = (0 + 1) = 1.
Example 3:
Input: list1 = ["happy","sad","good"], list2 = ["sad","happy","good"]
Output: ["sad","happy"]
Explanation: There are three common strings:
"happy" with index sum = (0 + 1) = 1.
"sad" with index sum = (1 + 0) = 1.
"good" with index sum = (2 + 2) = 4.
The strings with the least index sum are "sad" and "happy".
Constraints:
1 <= list1.length, list2.length <= 1000
1 <= list1[i].length, list2[i].length <= 30
list1[i] and list2[i] consist of spaces ' ' and English letters.
All the strings of list1 are unique.
All the strings of list2 are unique.
思路一：用两个 map 存储对应的下标，最后遍历最小的下标。优化，看了一下题解，发现不用两个 map，在遍历第二个数组的时候，此时已经能计算最小值了，直接存储当时的最小值结果就行
public String[] findRestaurant(String[] list1, String[] list2) {
Map<String, Integer> map1 = new HashMap<>();
Map<String, Integer> map2 = new HashMap<>();
for (int i = 0; i < list1.length; i++) {
map1.put(list1[i], i);
}
int min = Integer.MAX_VALUE;
for (int i = 0; i < list2.length; i++) {
if (map1.containsKey(list2[i])) {
int val = map1.get(list2[i]) + i;
min = Math.min(val, min);
map2.put(list2[i], val);
}
}
List<String> result = new ArrayList<>();
for (Map.Entry<String, Integer> e : map2.entrySet()) {
if (e.getValue() == min) {
result.add(e.getKey());
}
}
return result.toArray(new String[]{});
}