A. Whose sentence is it?
time limit per test
memory limit per test
input
output
lala." at the end of her sentences, while Rainbow always said "miao." at the beginning of his sentences. For each sentence in the chat record, help liouzhou_101 find whose sentence it is.
Input
n (1 ≤ n ≤ 10), number of sentences in the chat record. Each of the next n lines contains a sentence. A sentence is a string that contains only Latin letters (A-Z, a-z), underline (_), comma (,), point (.) and space ( ). Its length doesn’t exceed 100.
Output
Freda's" if the sentence was said by Freda, "Rainbow's" if the sentence was said by Rainbow, or "OMG>.< I don't know!" if liouzhou_101 can’t recognize whose sentence it is. He can’t recognize a sentence if it begins with "miao." and ends with "lala.", or satisfies neither of the conditions.
Sample test(s)
input
5 I will go to play with you lala. wow, welcome. miao.lala. miao. miao .
output
Freda's OMG>.< I don't know! OMG>.< I don't know! Rainbow's OMG>.< I don't know!
strstr(s,p) //在s中找p,返回指向第一个子串首的指针,若无返回NULL.
gets(s) //读入一行.
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<functional>
#include<cmath>
#include<cctype>
using namespace std;
#define For(i,n) for(int i=1;i<=n;i++)
#define Rep(i,n) for(int i=0;i<n;i++)
#define Fork(i,k,n) for(int i=k;i<=n;i++)
#define ForD(i,n) for(int i=n;i;i--)
#define Forp(x) for(int p=pre[x];p;p=next[p])
#define RepD(i,n) for(int i=n;i>=0;i--)
int n;
char s[1000+10],p1[10]="miao.",p2[10]="lala.";
int main()
{
// freopen("CF312A.in","r",stdin);
// freopen(".out","w",stdout);
scanf("%d",&n);gets(s);
while (n--)
{
gets(s);
int len=strlen(s);
bool b1=(strstr(s,p1))==s,b2=(strstr(s+strlen(s)-strlen(p2),p2)==(s+strlen(s)-strlen(p2)));
if (!(b1^b2)) puts("OMG>.< I don't know!");
else if (b1) puts("Rainbow's");
else puts("Freda's");
}
return 0;
}
标签:Whose,include,strstr,sentence,int,miao,know,312A,define From: https://blog.51cto.com/u_15724837/5793995