```cpp
struct bign {
int d[MaxM], len;
void clean() {
while (len > 1 && !d[len - 1]) len--;
}
bign() {
fill(d, d + MaxM, 0);
len = 1;
}
bign(int num) { *this = num; }
bign(string num) { *this = num; }
bign operator=(const string num) {
fill(d, d + MaxM, 0);
len = num.size();
for (int i = 0; i < len; i++) d[i] = num[len - 1 - i] - '0';
clean();
return *this;
}
bign operator=(int num) {
string s;
for (; num; num /= 10) s = char(num % 10 + '0') + s;
*this = s;
return *this;
}
bign operator+(const bign& b) {
bign c = *this;
int cnt;
for (cnt = 0; cnt < b.len; cnt++) {
c.d[cnt] += b.d[cnt];
c.d[cnt + 1] += c.d[cnt] / 10, c.d[cnt] %= 10;
}
while (c.d[cnt] > 9) c.d[cnt++] %= 10, c.d[cnt]++;
c.len = max(len, b.len);
if (c.d[cnt] && c.len <= cnt) c.len = cnt + 1;
return c;
}
bign operator-(const bign& b) {
bign c = *this;
int cnt;
for (cnt = 0; cnt < b.len; cnt++) {
c.d[cnt] -= b.d[cnt];
if (c.d[cnt] < 0) c.d[cnt] += 10, c.d[cnt + 1]--;
}
while (c.d[cnt] < 0) c.d[cnt++] += 10, c.d[cnt]--;
c.clean();
return c;
}
bign operator*(const bign& b) const {
bign c;
c.len = len + b.len + 2;
for (int i = 0; i < len; i++)
for (int j = 0; j < b.len; j++)
c.d[i + j] += d[i] * b.d[j];
for (int i = 0; i < c.len - 1; i++)
c.d[i + 1] += c.d[i] / 10, c.d[i] %= 10;
c.clean();
return c;
}
bign operator/(const bign& b) {
bign c = *this, a = 0;
for (int i = len - 1, j; i >= 0; i--) {
a = a * 10 + d[i];
for (j = 0; j < 10; j++)
if (a < b * (j + 1)) break;
c.d[i] = j;
a = a - b * j;
}
c.clean();
return c;
}
bign operator%(const bign& b) {
bign a = 0;
for (int i = len - 1, j; i >= 0; i--) {
a = a * 10 + d[i];
for (j = 0; j < 10; j++)
if (a < b * (j + 1)) break;
a = a - b * j;
}
return a;
}
bign operator+=(const bign& b) {
*this = *this + b;
return *this;
}
bool operator<(const bign& b) const {
if (len != b.len) return len < b.len;
for (int i = len - 1; i >= 0; i--)
if (d[i] != b.d[i]) return d[i] < b.d[i];
return false;
}
bool operator>(const bign& b) const { return b < *this; }
bool operator<=(const bign& b) const { return !(b < *this); }
bool operator>=(const bign& b) const { return !(*this < b); }
bool operator!=(const bign& b) const { return b < *this || *this < b; }
bool operator==(const bign& b) const { return !(b < *this) && !(b > *this); }
string str() const {
string s(len, '0');
for (int i = 0; i < len; i++) s[len - 1 - i] = d[i] + '0';
return s;
}
friend istream& operator>>(istream& in, bign& x) {
string s;
in >> s;
x = s.c_str();
return in;
}
friend ostream& operator<<(ostream& out, const bign& x) {
out << x.str();
return out;
}
} f[MaxN], k;
标签:cnt,const,len,板子,return,num,bign,高精
From: https://www.cnblogs.com/ybtarr/p/18335361