HDU 1020 Encoding

题目链接：HDU 1020【Encoding】

思路

       简单模拟，计算相同字母的连续子串个数。

代码

#include <iostream>
#include <algorithm>
#include <queue>
using namespace std;
#define ll long long
const int N = 500 + 10;

void solve() {
  string s;
  cin >> s;
  int len = s.length();
  for (int i = 0; i < len; i++) {
    int j = i;
    while (s[i] == s[j] && j < len)
      j++;
    if (j - i != 1) cout << j - i;
    cout << s[i];
    i = j - 1;
  }
  cout << endl;
  return;
}

int main() {
  int t;
  cin >> t;
  while (t--) {
    solve();
  }
  return 0;
}