task 4
#include <stdio.h> int main() { int count = 0; char c; FILE *fp ; fp = fopen("data4.txt", "r"); if (fp ==NULL) { printf("fail to open the file\n"); return 1; } while ((c = fgetc(fp)) != EOF) { if (c != ' ' && c != '\n' && c != '\t') { count++; } } fclose(fp); printf("data4.txt中共包含字符数(不计空白符):%d\n", count); return 0; }
task 5
#include<stdio.h> #include<string.h> #define N 10 typedef struct{ long int id; char name[20]; float objective; float subjective; float sum; char ans[10]; }STU; void finput(STU st[],int n); void foutput(STU st[],int n); void output(STU st[],int n); int process(STU st[],int n,STU st_pass[]); int main(){ STU stu[N],stu_pass[N]; int cnt; double pass_rate; printf("从文件读入%d个考生信息...\n",N); finput(stu,N); printf("\n对考生成绩进行统计...\n"); cnt=process(stu,N,stu_pass); printf("\n通过考试的考生完整信息:\n"); output(stu_pass,cnt); foutput(stu_pass,cnt); pass_rate=1.0*cnt/N; printf("\n本次等级考试通过率:%.2f%%\n",pass_rate*100); return 0;} void output(STU st[], int n) { int i; printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n"); for (i = 0; i < n; i++) printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", st[i].id, st[i].name, st[i].objective, st[i].subjective, st[i].sum, st[i].ans); } // 从文本文件examinee.txt读入考生信息:准考证号,姓名,客观题得分,操作题得分 void finput(STU st[], int n) { int i; FILE *fin; fin = fopen("examinee.txt", "r"); if (fin == NULL) { printf("fail to open file\n"); exit(0); } while (!feof(fin)) { for (i = 0; i < n; i++) fscanf(fin, "%ld %s %f %f", &st[i].id, st[i].name, &st[i].objective, &st[i].subjective); } fclose(fin); } // 把通过考试的考生完整信息写入文件list_pass.txt // 准考证号,姓名,客观题得分,操作题得分,总分,结果 void foutput(STU s[], int n) { FILE *fout; int i; // 保存到文件 fout = fopen("list_pass.txt", "w"); if (!fout) { printf("fail to open or create list_pass.txt\n"); exit(0); } fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n"); for (i = 0; i < n; i++) fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].ans); fclose(fout); } // 对考生信息进行处理:计算每位考生考试总分、结果;统计考试通过的人数 int process(STU st[], int n, STU st_pass[]) { int i,cnt=0; for(i=0;i<n;i++){ st[i].sum=st[i].objective + st[i].subjective; if(st[i].sum>=60){ strcpy(st[i].ans,"pass"); st_pass[cnt++] = st[i]; } else strcpy(st[i].ans,"fail"); } return cnt; }
task 6
#include <stdio.h> #include <string.h> #include <stdlib.h> #include <time.h> #define M 100 #define N 80 typedef struct { long int id; char name[10]; char c[20]; }STU; int main(){ STU st[M]; int i,n; FILE *fin; FILE *fp; fin = fopen("list.txt", "r"); if (fin == NULL) { printf("fail to open file\n"); exit(0); } while (!feof(fin)){ for(i=0;i<N;i++) fscanf(fin,"%ld %s %s",&st[i].id,st[i].name,st[i].c); } fp = fopen("lucky.txt", "wb"); if(fp == NULL) { printf("fail to open file\n"); return 1; } srand(time(0)); for(i=0;i<5;i++){ n=rand()%N; fprintf(fp,"%ld %-10s %-20s\n",st[n].id,st[n].name,st[n].c); printf("%ld %-10s %-20s\n",st[n].id,st[n].name,st[n].c); } fclose(fin); fclose(fp); return 0; }
标签:int,printf,st,STU,实验,pass,fin From: https://www.cnblogs.com/wp40032880/p/18260493