丑数的因子只能是2,3,5。但是可能有多个2,多个3,多个5.因此需要循环地除以2、3、5.
public class Solution {
public bool IsUgly(int n) {
if (n <= 0) {
return false;
}
int[] factors = {2, 3, 5};
for ( int i=0;i<3;i++) {
int factor=factors[i];
while (n % factor == 0) {
n /= factor;
}
}
return n == 1;
}
}
标签:丑数,return,factors,int,public,263,factor,leetcode
From: https://blog.csdn.net/zhourongxiang1/article/details/139410909