二分_查找

int main()
{
	int arr[] = { 1,2,3,4,5,6,7,8,9,10 };
	int k = 7;//要查找的数字
	//在这个arr有序数组中查找k的下标的值
	int sz = sizeof(arr) / sizeof(arr[0]);//数组的元素个数
	int left = 0;
	int right = sz - 1;
	while (left<=right)
	{
		int mid = (left + right) / 2;
		if (arr[mid] < k)
		{
			left = mid + 1;
		}
		else if (arr[mid] > k)
		{
			right = mid - 1;
		}
		else
		{
			printf("找到了,下标为：%d\n", mid);
			break;
		}
	}
	return 0;
}