/// <summary> /// 2022年10月17日 Author:Myzw /// /// </summary> [CommandMethod("Test14")] public void C_Test14() { var per1 = Autodesk.AutoCAD.ApplicationServices.Application.DocumentManager.MdiActiveDocument.Editor.GetEntity("\nPick Polyline 1"); if (per1.Status != PromptStatus.OK) return; var per2 = Autodesk.AutoCAD.ApplicationServices.Application.DocumentManager.MdiActiveDocument.Editor.GetEntity("\nPick Polyline 2"); if (per2.Status != PromptStatus.OK) return; using (Transaction tr = Autodesk.AutoCAD.ApplicationServices.Application.DocumentManager.MdiActiveDocument.TransactionManager.StartTransaction()) { BlockTable bt = (BlockTable)tr.GetObject(Autodesk.AutoCAD.ApplicationServices.Application.DocumentManager.MdiActiveDocument.Database.BlockTableId, OpenMode.ForRead, false); BlockTableRecord btr = (BlockTableRecord)tr.GetObject(bt[BlockTableRecord.ModelSpace], OpenMode.ForWrite, false); var cur1 = (per1.ObjectId.GetObject(OpenMode.ForRead) as Curve).GetGeCurve(); var cur2 = (per2.ObjectId.GetObject(OpenMode.ForRead) as Curve).GetGeCurve(); var cci = new CurveCurveIntersector3d(cur1, cur2, Vector3d.ZAxis); for (int i = 0; i < cci.NumberOfIntersectionPoints ; i++) { var pt = new DBPoint(cci.GetPointOnCurve1(i).Point); btr.AppendEntity(pt); tr.AddNewlyCreatedDBObject(pt, true); } tr.Commit(); } }
测试代码如上
当curve1为下图中的线段、curve2为多段线时,
得到的交点是错误的。
当curve1为多段线、curve2为线段时,
在附件的测试图中,
能得到正确的结果,
但在我的实际项目代码中,
即使我交换多段线和线段的顺序,
也无法获取正确的交点。
解决方法:
当曲线是线段或圆弧时,
将其拆分,
创建新的组合曲线,
之后用新建的组合曲线求交点,
可以得到正确的结果。
标签:OpenMode,AutoCAD,Geometry,MdiActiveDocument,tr,CurveCurveIntersector3d,Applicati From: https://www.cnblogs.com/myzw/p/16801316.html