class Solution {
public:
void rotate(vector<vector<int>>& matrix) {
int n = matrix.size();
for (int i = 0; i < n / 2; ++i) {
for (int j = 0; j < (n + 1) / 2; ++j) {
int temp = matrix[i][j];
matrix[i][j] = matrix[n - j - 1][i];
matrix[n - j - 1][i] = matrix[n - i - 1][n - j - 1];
matrix[n - i - 1][n - j - 1] = matrix[j][n - i - 1];
matrix[j][n - i - 1] = temp;
}
}
}
};
2、https://leetcode.cn/problems/set-matrix-zeroes/?envType=study-plan-v2&envId=2024-spring-sprint-100
class Solution {
public:
void setZeroes(vector<vector<int>>& matrix) {
int m=matrix.size(),n=matrix[0].size();
int temp[m][n];
memset(temp,-1,sizeof(temp));
for(int i=0;i<m;i++){
for(int j=0;j<n;j++){
if(matrix[i][j]==0){
temp[i][j]=1;
}
}
}
for(int i=0;i<m;i++){
for(int j=0;j<n;j++){
if(temp[i][j]==1){
for(int k=0;k<m;k++)
matrix[k][j]=0;
for(int k=0;k<n;k++)
matrix[i][k]=0;
}
}
}
}
};
标签:cn,matrix,temp,int,spring,day10,size,LeetCode,刷题
From: https://www.cnblogs.com/humanplug/p/18120387