题目:
链接:https://www.luogu.com.cn/problem/P1833
知识点:二进制优化,完全背包
emm怎么说呢,还是被卡内存,所以自顶而下编程不好!还是用滚动数组好点
代码:
#include<iostream>
#include<vector>
#include<algorithm>
#include<math.h>
#include<sstream>
#include<string>
#include<string.h>
#include<iomanip>
#include<stdlib.h>
#include<map>
#include<queue>
#include<limits.h>
#include<climits>
#include<fstream>
#include<stack>
typedef unsigned long long ll;
using namespace std;
const int N = 1e5+10;
int t[N], c[N], p[N];
int dp[2][1010];
int main()
{
int times;
int n;
ios::sync_with_stdio(false);
cin.tie(nullptr);
int te1, te2, ts1, ts2;
char cc;
cin >> te1 >> cc >> te2 >> ts1 >> cc >> ts2 >>n;
times = 60 * (ts1 - te1) + ts2 - te2;
ll id = 1;
//在线进制拆分
for (int i = 1; i <= n; i++)
{
cin >> t[id] >> c[id] >> p[id];
if (p[id] > 1)
{
int timesa = p[id];
int oct = t[id];
int occ = c[id];
for (int y = 1; y <= timesa; y <<= 1)
{
t[id] = y * oct;
c[id] = y * occ;
p[id] = y;
timesa -= y;
id++;
}
if (timesa)
{
t[id] = timesa * oct;
c[id] = timesa * occ;
p[id] = timesa;
id++;
}
}
else if (p[id] == 0)
{
ll timesa = times;
ll oct = t[id];
ll occ = c[id];
for (int y = 1; y <= timesa; y <<= 1)
{
t[id] = y * oct;
c[id] = y * occ;
p[id] = y;
timesa -= y;
id++;
}
if (timesa)
{
t[id] = timesa * oct;
c[id] = timesa * occ;
p[id] = timesa;
id++;
}
}
else id++;
}
id--;
int now =0;
//背包
for (int i = 1; i <= id; i++)
{
now=1-now;
for (int j = 0; j <= times; j++)
if (t[i] > j)dp[now][j] = dp[1-now][j];
else dp[now][j] = max(dp[1-now][j], dp[1-now][j - t[i]] + c[i]);
}
cout << dp[now][times];
return 0;
}
标签:樱花,now,int,P1833,te1,include,id,dp
From: https://www.cnblogs.com/zzzsacmblog/p/18116175