import java.util.Scanner;
public class Main {
static final int N = 200005;
static long n, m;
static int[] a = new int[N];
static int[] b = new int[N];
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
n = sc.nextLong();
m = sc.nextLong();
for (int i = 1; i <= n; ++i) a[i] = sc.nextInt();
for (int i = 1; i <= n; ++i) b[i] = sc.nextInt();
//准备开始进行二分查找
int l = 0, r = N * 2;
while (l < r) {
int mid = (l + r + 1) >> 1;
if (check(mid)) l = mid;
else r = mid - 1;
}
System.out.println(r);
}
public static boolean check(int x) {
long v = m;//现在拥有的卡牌数
for (int i = 1; i <= n; ++i) {
if (a[i] >= x) continue;
if (a[i] + b[i] < x) return false;
if (a[i] + b[i] >= x && v >= x - a[i])
v -= (x - a[i]);
else return false;
}
return true;
}
}
标签:return,Scanner,真题,int,mid,卡牌,蓝桥,static,new
From: https://blog.csdn.net/qq_30500575/article/details/137383049