一道有趣的思维题
经过推理,最后的答案只有两种构成:
1.1的数目*2的数目
2.所有相同的数n,进行C(2,n)然后相加
像这样,然后把比值设成k,可以知道只能枚举如上两类
https://codeforces.com/problemset/problem/1899/D
#include<iostream>
#include<vector>
#include<algorithm>
#include<math.h>
#include<sstream>
#include<string>
#include<string.h>
#include<iomanip>
#include<stdlib.h>
#include<map>
#include<queue>
#include<limits.h>
#include<climits>
#include<fstream>
#include<stack>
typedef long long ll;
using namespace std;
queue<ll>id;
int main()
{
int t; cin >> t;
for (int ii = 0; ii < t; ii++)
{
map<ll, ll>mplst;
ll ans = 0;
int n; cin >> n; int xx;
if (n == 1) { cout << 0 << endl; cin >> xx; }
else
{
for (int i = 0; i < n; i++)
{
cin >> xx;
if (!mplst[xx])id.push(xx);
mplst[xx]++;
}
ans += mplst[1] * mplst[2];//第一类
while (!id.empty())
{
ll idx = id.front();
id.pop();
if (mplst[idx] > 1)ans += mplst[idx] * (mplst[idx] - 1) / 2;//第二类
}
cout << ans << endl;
}
}
return 0;
}
标签:idx,int,Yarik,Notes,id,xx,mplst,include,Musical
From: https://www.cnblogs.com/zzzsacmblog/p/18090497