Dijkstra(迪杰斯特拉)

朴素Dijkstra

时间复杂度O(n^2)

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define endl "\n"
#define fi first
#define se second
#define pb push_back
#define pll pair<ll,ll>
const ll mod=1e9+7;
const ll N=3e3+9;
bool book[N];
ll a[N][N],b[N];
ll n,m,s,t;
void f1(ll s)
{
	for(ll i=1;i<=n;i++)
		b[i]=a[s][i];
	for(ll i=1;i<=n;i++)
	{
		ll t=-1;
		for(ll j=1;j<=n;j++)
			if(!book[j]&&(t==-1||b[t]>b[j]))
				t=j;
		book[t]=true;
		for(ll j=1;j<=n;j++)
			b[j]=min(b[j],b[t]+a[t][j]);
	}
}
void f0(ll T)
{
	cin>>n>>m>>s>>t;
	for(ll i=1;i<=n;i++)
		for(ll j=1;j<=n;j++)
			if(i==j)
				a[i][j]=0;
			else
				a[i][j]=1e9;
	while(m--)
	{
		ll x,y,z;
		cin>>x>>y>>z;
		a[x][y]=a[y][x]=min(a[x][y],z);
	}
	f1(s);
	cout<<b[t]<<endl;
}
int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	ll T=1;
//	cin>>T;
	for(ll i=1;i<=T;i++)
		f0(i);
	return 0;
}

堆优化Dijkstra

时间复杂度O(mlog(n))

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define endl "\n"
#define fi first
#define se second
#define pb push_back
#define pll pair<ll,ll>
const ll mod=1e9+7; 
const ll N=7e3*2+9;
struct pp
{
	ll x,y,z;
}p[N];
bool book[N];
ll a[N],b[N];
ll n,m,s,t,k;
void dijkstra(ll s)
{
	priority_queue<pll,vector<pll>,greater<pll>>q;
	for(ll i=1;i<=n;i++)
	{
		b[i]=1e18;
		book[i]=false;
	}	
    b[s]=0;
    q.push({0,s});
    while(q.size())
    {
        ll x=q.top().se;
        q.pop();
        if(book[x])
        	continue;
        book[x]=true;
        for(ll i=a[x];i!=-1;i=p[i].x)
        {
            ll y=p[i].y;
            if(b[y]>b[x]+p[i].z)
            {
                b[y]=b[x]+p[i].z;
                q.push({b[y],y});
            }
        }
    }
}
void add(ll x,ll y,ll z)
{
	p[k].x=a[x];
	p[k].y=y;
	p[k].z=z;
	a[x]=k++;
}
void f0(ll T)
{
    k=0;
    cin>>n>>m>>s>>t;
    memset(a,-1,sizeof a);
    memset(p,0,sizeof p);
    while(m--)
    {
    	ll x,y,z;
    	cin>>x>>y>>z;
        add(x,y,z);
        add(y,x,z);
    }
    dijkstra(s);
    cout<<b[t]<<endl;
}
int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	ll T=1;
//	cin>>T;
	for(ll i=1;i<=T;i++)
		f0(i);
	return 0;
}