首页 > 其他分享 >多个生产者,单个消费者,互斥锁

多个生产者,单个消费者,互斥锁

时间:2022-10-10 11:12:12浏览次数:53  
标签:count min 生产者 单个 互斥 mutex pthread shared include

#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>

#define min(a,b) ((a)<(b)?(a):(b))
#define MAXNITEMS   1000000
#define MAXNTHREADS 10

int nitems;
struct {
	pthread_mutex_t mutex;
	int buff[MAXNITEMS];
	int nput;
	int nval;
}shared={
	PTHREAD_MUTEX_INITIALIZER
};

void *produce(void *), *consume(void *);

int main(int argc, char **argv) {
	int i, nthreads, count[MAXNTHREADS];
	pthread_t tid_produce[MAXNTHREADS], tid_consume;

	if(argc!=3) {
		fprintf(stderr, "usage: ./a.out <#items> <#threads>.\n");
		exit(-1);
	}
	nitems=min(atoi(argv[1]), MAXNITEMS);
	nthreads=min(atoi(argv[2]), MAXNTHREADS);

	pthread_setconcurrency(nthreads);

	for(i=0;i<nthreads;i++) {
		count[i]=0;
		pthread_create(&tid_produce[i], NULL, produce, &count[i]);
	}

	for(i=0;i<nthreads;i++) {
		pthread_join(tid_produce[i], NULL);
		printf("count[%d]=%d\n", i, count[i]);
	}

	pthread_create(&tid_consume, NULL, consume, NULL);
	pthread_join(tid_consume, NULL);

	exit(0);
}

void *produce(void *arg) {
	for(;;)	{
		pthread_mutex_lock(&shared.mutex);
		if(shared.nput>=nitems) {
			pthread_mutex_unlock(&shared.mutex);
			return NULL;
		}
		shared.buff[shared.nput]=shared.nval;
		shared.nput++;
		shared.nval++;
		pthread_mutex_unlock(&shared.mutex);
		*((int *)arg)+=1;
	}
}

void *consume(void *arg) {
	int i;
	for(i=0;i<nitems;i++) {
		if(shared.buff[i]!=i) {
			printf("buff[%d]=%d\n", i, shared.buff[i]);
		}
	}
	return NULL;
}

结果如下:

$ gcc prodcons.c -pthread
$ ./a.out 10000000 5
count[0]=253230
count[1]=285783
count[2]=129999
count[3]=157355
count[4]=173633

标签:count,min,生产者,单个,互斥,mutex,pthread,shared,include
From: https://www.cnblogs.com/donggongdechen/p/16774914.html

相关文章