a = [{'name': 'b', 'age': 11}, {'name': 'c', 'age': 10}, {'name': 'a', 'age': 12}]
e = {'name': 22, 'age': 12, 'bbb': 23}
b = sorted(a, key=lambda d: d['age'], reverse=True)
f = dict(sorted(e.items(), key=lambda item: item[1], reverse=True))
print(b)
print(f)
标签：name,字典,age,print,排序,True,lambda From： https://www.cnblogs.com/lytcreate/p/17849655.html