题目
Given a binary tree, find its minimum depth.
The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.
Note: A leaf is a node with no children.
Example:
Given binary tree [3,9,20,null,null,15,7]
,
3
/ \
9 20
/ \
15 7
return its minimum depth = 2.
题目大意
给定一个二叉树,找出其最小深度。最小深度是从根节点到最近叶子节点的最短路径上的节点数量。说明: 叶子节点是指没有子节点的节点。
解题思路
- 递归求出根节点到叶子节点的深度,输出最小值即可
参考代码
package leetcode
import (
"github.com/halfrost/LeetCode-Go/structures"
)
// TreeNode define
type TreeNode = structures.TreeNode
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func minDepth(root *TreeNode) int {
if root == nil {
return 0
}
if root.Left == nil {
return minDepth(root.Right) + 1
}
if root.Right == nil {
return minDepth(root.Left) + 1
}
return min(minDepth(root.Left), minDepth(root.Right)) + 1
}
func min(a int, b int) int {
if a > b {
return b
}
return a
}
标签:Binary,minDepth,TreeNode,int,Tree,Depth,return,root,节点
From: https://blog.51cto.com/u_16110811/8433696