题目
Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as:
a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
Example 1:
Given the following tree [3,9,20,null,null,15,7]:
3
/ \
9 20
/ \
15 7
Return true.
Example 2:
Given the following tree [1,2,2,3,3,null,null,4,4]:
1
/ \
2 2
/ \
3 3
/ \
4 4
Return false.
题目大意
判断一棵树是不是平衡二叉树。平衡二叉树的定义是:树中每个节点都满足左右两个子树的高度差 <= 1 的这个条件。
解题思路
根据定义判断即可,计算树的高度是第 104 题。
参考代码
package leetcode
import (
"github.com/halfrost/LeetCode-Go/structures"
)
// TreeNode define
type TreeNode = structures.TreeNode
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func isBalanced(root *TreeNode) bool {
if root == nil {
return true
}
leftHight := depth(root.Left)
rightHight := depth(root.Right)
return abs(leftHight-rightHight) <= 1 && isBalanced(root.Left) && isBalanced(root.Right)
}
func depth(root *TreeNode) int {
if root == nil {
return 0
}
return max(depth(root.Left), depth(root.Right)) + 1
}
func abs(a int) int {
if a > 0 {
return a
}
return -a
}
func max(a int, b int) int {
if a > b {
return a
}
return b
}
标签:Binary,TreeNode,binary,int,tree,Tree,110,return,null
From: https://blog.51cto.com/u_16110811/8408112