截断爆破

from multiprocessing.dummy import Pool as tp
import hashlib

knownMd5 = 'c4d038'  # 已知的md5明文


def md5(text):
    return hashlib.md5(str(text).encode('utf-8')).hexdigest()


def findCode(code):
    key = code.split(':')
    end = int(key[1])
    start = int(key[0])
    for code in range(start, end):
        if md5(code)[0:6] == knownMd5:
            print(code)


list = []
for i in range(1):  # 这里的range(number)指爆破出多少结果停止
    list.append(str(10000000 * i) + ':' + str(10000000 * (i + 1)))
pool = tp()  # 使用多线程加快爆破速度
pool.map(findCode, list)
pool.close()
pool.join()

残缺爆破

import hashlib
text = 'LitCTF{md5can3derypt213thoughcrsh}'
list1 = 'abcdefghijklmnopqrstuvyxyz0123456789'
for i in list1:
    for j in list1:
        for k in list1:
            for l in list1:
                text1 = list(text)
                text1.insert(13, i)
                text1.insert(14, j)
                text1.insert(18, k)
                text1.insert(34, l)
                text3 = ''.join(text1)
                text2 = hashlib.md5(text3.encode()).hexdigest()
                if text2 == '496603d6953a15846cd7cc476f146771':
                    print(text3)
                    print(i, j, k, l)