c语言代码练习12

\\计算1/1-1/2+1/3...-1/100的和
#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>


int main()
{
    int x = 0;
    double sum = 0.0;
    int n = 1; 
    for (x = 1; x <= 100; x++)
    {
        sum += n*1.0 / x;
        n = -n;
    }
    printf("1-1/2+1/3-...-1/100的值为:%lf", sum);
    return 0;
}