class Solution:
def simplifyPath(self, path: str) -> str:
li=path.split("/")
res=[]
for i in li:
if i=='..' and res:
res.pop()
if i!='.' and i!='..' and set(i)!=set(''):
res.append(i)
return '/'+"/".join(res)
标签：leetcode71,..,res,路径,li,set,简化,str From： https://www.cnblogs.com/tanyuanqing/p/17709262.html