参考地址
一开始连题意都没搞懂就开始直接做,too young。应该静下来用5分钟分析,by the way, may be the typical usage of brute-force is “void” function instead of function with return value.
//#define LOCAL
#include <cstdio>
#include <cstring>
#include <string>
#include <cmath>
#include <ctype.h>
#include <algorithm>
#define SIZE 10
using namespace std;
int map[SIZE];
int brute(int size){
if(size == 1)
return map[0];
else if(size == 2)
return abs(map[0] - map[1]);
int ans = -1;
int mid = size / 2;
do{
if(map[0] != 0 && map[mid] != 0){
int x = 0;
int y = 0;
for(int i = 0; i < mid; i++)
x = x * 10 + map[i];
for(int i = mid; i < size; i++)
y = y * 10 + map[i];
if(ans == -1 || ans > abs(x - y))
ans = abs(x - y);
/*for(int i = 0; i < size; i++)
printf("%d ", map[i]);
printf("\n");
printf("x:%d y:%d\n", x, y);*/
}
}while(next_permutation(map, map + size));
return ans;
}
int main(){
#ifdef LOCAL
freopen("data.in", "r", stdin);
#endif
int n;
scanf("%d", &n);
getchar();
while(n--){
int pos = 0;
char c;
while(scanf("%c", &c), c != '\n'){
if(c != ' ')
map[pos++] = c - '0';
}
/*for(int j = 0; j < pos; j++)
printf("%d ", map[j]);
printf("\n");*/
//printf("%d", pos);
printf("%d\n", brute(pos));
}
return 0;
}