1. 题目

读题

HJ92 在字符串中找出连续最长的数字串

考查点

2. 解法

思路

代码逻辑

具体实现

自行实现

public class HJ092 {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        while (sc.hasNext()) {
            String[] ans = getLongestDigitChar(sc.nextLine());
            System.out.println(ans[0] + "," + ans[1]);
        }
    }

    public static String[] getLongestDigitChar(String str) {
        String[] ans = new String[2];

        int max = 0;
        StringBuffer sb = new StringBuffer();
        int i = 0;
        char[] chars = str.toCharArray();
        while (i < chars.length) {
            char c = chars[i];

            if (!Character.isDigit(c)) {
                i++;
                continue;
            }

            int curCnt = 0;
            while (i < chars.length && Character.isDigit(chars[i])) {
                curCnt++;
                i++;
            }
            String cur = str.substring(i - curCnt, i);
            if (curCnt > max) {
                max = curCnt;
                sb = new StringBuffer(cur);
            } else if (curCnt == max) {
                sb.append(cur);
            }
        }
        ans[0] = sb.toString();
        ans[1] = max + "";
        return ans;
    }
}

3. 总结