难度中等
给你 二维 平面上两个 由直线构成且边与坐标轴平行/垂直 的矩形,请你计算并返回两个矩形覆盖的总面积。
每个矩形由其 左下 顶点和 右上 顶点坐标表示:
- 第一个矩形由其左下顶点
(ax1, ay1)
和右上顶点(ax2, ay2)
定义。 - 第二个矩形由其左下顶点
(bx1, by1)
和右上顶点(bx2, by2)
定义。
示例 1:
输入:ax1 = -3, ay1 = 0, ax2 = 3, ay2 = 4, bx1 = 0, by1 = -1, bx2 = 9, by2 = 2 输出:45
示例 2:
输入:ax1 = -2, ay1 = -2, ax2 = 2, ay2 = 2, bx1 = -2, by1 = -2, bx2 = 2, by2 = 2 输出:16
提示:
-104 <= ax1, ay1, ax2, ay2, bx1, by1, bx2, by2 <= 104
class Solution: def computeArea(self, ax1: int, ay1: int, ax2: int, ay2: int, bx1: int, by1: int, bx2: int, by2: int) -> int: cx1 = max(ax1,bx1) cy1 = max(ay1,by1) cx2 = min(ax2,bx2) cy2 = min(ay2,by2) dx = max(0, cx2-cx1) dy = max(0, cy2-cy1) def get_area(ax1,ax2,ay1,ay2): return (ax2-ax1) * (ay2-ay1) return get_area(ax1,ax2,ay1,ay2) + get_area(bx1,bx2,by1,by2) - dx*dy
标签:ax2,ax1,int,ay1,面积,bx1,矩形,223,ay2 From: https://www.cnblogs.com/zle1992/p/17519970.html