#include <iostream>
#include <thread>
#include <array>
#include <functional>
template <auto func, std::size_t I>
struct param_type;
template <typename Ret, typename... Args, Ret (*func)(Args...), std::size_t I>
struct param_type<func, I>
{
using type = std::tuple_element_t<I, std::tuple<Args...>>;
};
template <typename Ret, typename... Args, Ret (*func)(Args..., ...), std::size_t I>
struct param_type<func, I>
{
using type = std::tuple_element_t<I, std::tuple<Args...>>;
};
void foo(std::string const&, int, char&) {
//...
}
static_assert(std::is_same_v<const std::string&, param_type<&foo, 0>::type>);
static_assert(std::is_same_v<int, param_type<&foo, 1>::type>);
static_assert(std::is_same_v<char&, param_type<&foo, 2>::type>);
https://stackoverflow.com/questions/70612294/getting-parameter-type-of-function-with-templates
标签：function,std,type,same,static,template,include,parameter From： https://www.cnblogs.com/Searchor/p/17490406.html