实验七
task1_1
程序源代码
// 将图书信息写入文本文件data1.txt #include <stdio.h> #define N 7 #define M 80 typedef struct { char name[M]; // 书名 char author[M]; // 作者 } Book; int main() { Book x[N] = { {"《雕塑家》", "斯科特.麦克劳德"}, {"《灯塔》", "克里斯多夫.夏布特"}, {"《五号屠宰场》", "库尔特.冯内古特"}, {"《出卖月亮的人》", "罗伯特.海因莱茵"}, {"《大地之上》", "罗欣顿·米斯特里"}, {"《上学记》", "何兆武"}, {"《命运》", "蔡崇达"} }; int i; FILE *fp; // 以写的方式打开文本文件data1.txt fp = fopen("data1.txt", "w"); // 如果打开文件失败,输出提示信息并返回 if(fp == NULL) { printf("fail to open file\n"); return 1; } // 将结构体数组x中的图书信息写到fp指向的文件data1.txt // 同时也输出到屏幕上 for(i = 0; i < N; ++i){ fprintf(fp, "%-20s %-20s\n", x[i].name, x[i].author); printf("%-20s %-20s\n", x[i].name, x[i].author); } fclose(fp); return 0; }
程序运行截图
task1_2
程序源代码
// 从文本文件data1.txt中读取图书信息,并打印输出到屏幕 #include <stdio.h> #define N 10 #define M 80 typedef struct { char name[M]; // 书名 char author[M]; // 作者 } Book; int main() { Book x[N]; int i, n; FILE *fp; // 以读的方式打开文本文件data1.txt fp = fopen("data1.txt", "r"); // 如果打开文件失败,输出提示信息并返回 if(fp == NULL) { printf("fail to open file\n"); return 1; } // 从文件中读取图书信息,保存到结构体数组x中 i = 0; while(!feof(fp)) { fscanf(fp, "%s%s", x[i].name, x[i].author); ++i; } n = i - 1; // 将图书信息打印输出到屏幕上 for(i = 0; i < n; ++i) printf("%d. %-20s%-20s\n", i+1, x[i].name, x[i].author); fclose(fp); return 0; }
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讨论:
若将 n = i - 1改为n = i.则结果如下
读取图书信息化后,i = 8,所以需要减1,、使i从0遍历到6
task4
程序源代码
#include <stdlib.h> #include <stdio.h> int main() { FILE *fp; int i=0; char ch; fp=fopen("data4.txt","r"); if(fp==NULL) { printf("fail to open\n"); return 1; } while(!feof(fp)) {ch=fgetc(fp); if(ch>33) i++; } fclose(fp); printf("共包含字符数%d",i); return 0 ; }
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task5
程序源代码
#include <stdio.h> #include <string.h> #include <stdlib.h> #define N 10 typedef struct { long int id; char name[20]; float objective; // 客观题得分 float subjective; // 操作题得分 float sum; char level[10]; } STU; // 函数声明 void input(STU s[], int n); void output(STU s[], int n); void process(STU s[], int n); int main() { STU stu[N]; printf("从文件读入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作题得分(<=60)\n", N); input(stu, N); printf("\n对考生信息进行处理: 计算总分,确定等级\n"); process(stu, N); printf("\n打印考生完整信息, 并保存到文件中"); output(stu, N); return 0; } // 从文本文件examinee.txt读入考生信息:准考证号,姓名,客观题得分,操作题得分 void input(STU s[], int n) { int i; FILE *fin; fin = fopen("examinee.txt", "r"); if (fin == NULL) { printf("fail to open file\n"); exit(0); } while (!feof(fin)) { for (i = 0; i < n; i++) fscanf(fin, "%ld %s %f %f", &s[i].id, s[i].name, &s[i].objective, &s[i].subjective); } fclose(fin); } // 输出考生完整信息: 准考证号,姓名,客观题得分,操作题得分,总分,等级 // 不仅输出到屏幕上,还写到文本文件result.txt中 void output(STU s[], int n) { FILE *fout; int i; // 输出到屏幕 printf("\n"); printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n"); for (i = 0; i < n; i++) printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level); // 保存到文件 fout = fopen("result.txt", "w"); if (!fout) { printf("fail to open or create result.txt\n"); exit(0); } fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n"); for (i = 0; i < n; i++) fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level); fclose(fout); } // 对考生信息进行处理:计算总分,排序,确定等级 void process(STU s[], int n) { int i, j; STU p; for (i = 0;i < n; ++i) { s[i].sum=s[i].objective+s[i].subjective; } for(j=1;j<n;j++) { if(s[j-1].sum<s[j].sum) { p=s[j]; s[j]=s[j-1]; s[j-1]=p; } } for(i=0;i<n*0.1;i++) strcpy(s[i].level,"优秀"); for(;i<n*0.5;i++) strcpy(s[i].level,"合格"); for(i;i<n;i++) strcpy(s[i].level,"不合格"); }
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task6
程序源代码
#include <stdlib.h> #include <stdio.h> #include <time.h> #define N 80 typedef struct { long int id; char name[N]; char classname[N]; }STU; void input (STU s[], int n); void process (STU s[], int n); int main() { STU stu[N]; input (stu, N); process (stu, N); return 0; } void input (STU s[], int n) { int i; FILE *fin; fin = fopen("list.txt", "r"); if (fin == NULL) { printf("fail to open file\n"); exit (0); } while (!feof(fin)) { for(i = 0; i< n;i++){ fscanf(fin,"%ld %s %s",&s[i].id,s[i].name,s[i].classname);} } fclose (fin); } void process (STU s[], int n) { int b[5]; int i; srand(time(NULL)); for (i = 0;i < 5; ++i) { b[i] = rand()%80 + 1; } for(i=0;i<5;i++) { printf("%ld\t%s\t%s\n",s[b[i]].id,s[b[i]].name,s[b[i]].classname); } FILE *fout; fout = fopen("lucky.txt","w"); if(!fout) { printf("fail to open or creat lucky.txt\n"); exit (0); } for(i=0;i<5;i++) fprintf(fout,"%ld\t%s\t%s\n",s[b[i]].id,s[b[i]].name,s[b[i]].classname); fclose(fout); }
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标签:fp,txt,name,int,STU,实验,include From: https://www.cnblogs.com/csy426/p/17467199.html