Given an integer array nums
, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
Example:
Input: [-2,1,-3,4,-1,2,1,-5,4]
,Output: 6
Explanation: [4,-1,2,1]
has the largest sum = 6
.
Follow up:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
贪心:
class Solution(object):
def maxSubArray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
ans = s = nums[0]
for i in xrange(1, len(nums)):
if s > 0:
s = nums[i]+s
else:
s = nums[i]
ans = max(s, ans)
return ans
DP解法://dp[i] means the maximum subarray ending with A[i];
class Solution(object):
def maxSubArray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
dp = [0]*len(nums)
ans = dp[0] = nums[0]
for i in xrange(1, len(nums)):
dp[i] = max(dp[i-1]+nums[i], nums[i])
ans = max(ans, dp[i])
return ans
递归解法:
TODO
标签:return,nums,int,sum,53,ans,Subarray,leetcode,dp From: https://blog.51cto.com/u_11908275/6381011