task 1源代码:
print(sum) sum = 42 print(sum) def inc(n): sum = n+1 print(sum) return sum sum = inc(7) + inc(7) print(sum)
问题:task1.py源码中,共有4处有python语句 print(sum) (line1, line3, line7, line11)。
这4处使用的标识符sum是同一个对象的名称吗?如果不是,请以文字方式回答这4处中标识符 sum的作用域。 答:不是。line1为内置作用域 ,line3和line11为全局作用域,line7为局部作用域task 2-1 源代码:
def func1(a, b, c, d, e, f): ''' 返回参数a,b,c,d,e,f构成的列表 默认,参数按位置传递; 也支持关键字传递 ''' return [a, b, c, d, e, f] def func2(a, b, c, *, d, e, f): ''' 返回参数a,b,c,d,e,f构成的列表 *后面的参数只能按关键字传递 ''' return [a, b, c, d, e, f] def func3(a, b, c, /, d, e, f): ''' 返回参数a,b,c,d,e,f构成的列表 /前面的参数只能按位置传递 ''' return [a, b, c, d, e, f] # func1调用:按位置传递、按参数传递都可以 print(func1(1, 9, 2, 0, 5, 3)) print(func1(a=1, b=9, c=2, d=0, e=5, f=3)) print(func1(1, 9, 2, f=3, d=0, e=5)) # func2调用:d,e,f必须按关键字传递 print( func2(11, 99, 22, d=0, e=55, f=33) ) print( func2(a=11, b=99, c=22, d=0, e=55, f=33) ) # func3调用:a,b,c必须按位置传递 print( func3(111, 999, 222, 0, 555, 333)) print( func3(111, 999, 222, d=0, e=555, f=333) )
task2-2 源代码:
list1 = [1, 9, 8, 4] print(sorted(list1)) print(sorted(list1, reverse=True)) print(sorted(list1, True))
![](/i/l/?n=23&i=blog/3128947/202305/3128947-20230523200744483-13548024.png)
问题:python内置函数sorted()中,参数reverse的传递方式是否必须使用关键字传递?
答:是。 task2-3源代码:def func(a, b, c, /, *, d, e, f): return ([a, b, c, d, e, f]) print(func(1, 2, 3, d=4, e=5, f=6))
![](/i/l/?n=23&i=blog/3128947/202305/3128947-20230523200848240-2125333931.png)
task3源代码:
def solve(a, b, c): ''' 求解一元二次方程, 返回方程的两个根 :para: a,b,c: float 方程系数 :return: tuple ''' delta = b*b - 4*a*c delta_sqrt = abs(delta)**0.5 p1 = -b/2/a p2 = delta_sqrt/2/a if delta >= 0: root1 = p1 + p2 root2 = p1 - p2 else: root1 = complex(p1, p2) root2 = complex(p1, -p2) return root1, root2 while True: try: t = input('输入一元二次方程系数a b c, 或者,输入#结束: ') if t == '#': print('结束计算,退出') break a, b, c = map(float, t.split()) if a == 0: raise ValueError('a = 0, 不是一元二次方程') except ValueError as e: print(repr(e)) print() except: print('有其它错误发生\n') else: root1, root2 = solve(a, b, c) print(f'root1 = {root1:.2f}, root2 = {root2:.2f}') print()
task4源代码:
def list_generator(x, y, s=1): l = [] while x <= y: l.append(x) x = x+s return l list1 = list_generator(-5, 5) print(list1) list2 = list_generator(-5, 5, 2) print(list2) list3 = list_generator(1, 5, 0.5) print(list3)
task5源代码:
def is_prime(n): if n == 2: return True else: for i in range(2, int(n**0.5)+1): if n % i == 0: return False return True for i in range(4, 21, 2): for s in range(2, i): if is_prime(i-s): print(f'{i} = {s} + {i-s}') break
task6源代码:
# 编码函数encoder()定义 def encoder(a): c = '' for i in a: if i.isalpha(): temp = ord(i)+5 if chr(temp).isalpha(): c += chr(temp) else: c += chr(temp-26) else: c += i return c # 解码函数decoder()定义 def decoder(x): z = '' for i in x: if i.isalpha(): temp = ord(i)-5 if chr(temp).isalpha(): z += chr(temp) else: z += chr(temp+26) else: z += i return z # 主体代码逻辑 text = input('输入英文文本:') encoded_text = encoder(text) print('编码后的文本: ', encoded_text) decoded_text = decoder(encoded_text) print('对编码后的文本解码: ', decoded_text)
task7源代码:
def Collatz(n): if n % 2 == 0: return n//2 else: return n*3+1 try: n = int(input('Enter a positive integer:')) if n <= 0: raise ValueError num = [n] while True: n = Collatz(n) num.append(n) if n == 1: print(num) break except ValueError: print('Error: must be a positive integer')
task8源代码:
def func(n): while True: if n == 1: return 1 else: return 2*func(n-1)+1 while True: x = input() if x == '#': print('计算结束') break n = int(x) ans = func(n) print(f'n = {n}, ans = {ans}')
标签:return,sum,else,实验,print,源代码,def From: https://www.cnblogs.com/prefectdown/p/17426275.html