方法一: 使用as_completed函数
from concurrent.futures import ThreadPoolExecutor, as_completed from time import sleep def method(times): sleep(times) print('sleep {} secondes'.format(times)) return times pool = ThreadPoolExecutor(max_workers=2) seconds = [i for i in range(10)] tasks = [pool.submit(method, (second)) for second in seconds] # as_completed函数会将运行完的任务一个一个yield出来 # 它返回任务的结果与提交任务的顺序无关,谁先执行完返回谁 for future in as_completed(tasks): print(future.result())
方法二: 使用map方法
from concurrent.futures import ThreadPoolExecutor from time import sleep def method(times): sleep(times) print('sleep {} secondes'.format(times)) return times pool = ThreadPoolExecutor(max_workers=2) seconds = [i for i in range(4)] # map方法会将任务运行的结果yield出来 # map方法返回任务结果的顺序与提交任务的顺序一致 for data in pool.map(method, seconds): print(data)
3.wait方法
wait方法用于阻塞主线程的运行, 可以设置当某些子线程运行完成以后再继续执行主线程其第一个参数是future对象或future对象列表,return_when参数用于指定当哪些任务运行完成时继续执行主线程,其参数有:
FIRST_COMPLETED = 'FIRST_COMPLETED'
FIRST_EXCEPTION = 'FIRST_EXCEPTION'
ALL_COMPLETED = 'ALL_COMPLETED'
from concurrent.futures import ThreadPoolExecutor, wait, ALL_COMPLETED, FIRST_COMPLETED import time # 参数times用来模拟网络请求的时间 def get_html(times): time.sleep(times) print("get page {}s finished".format(times)) return times executor = ThreadPoolExecutor(max_workers=2) urls = [3, 2, 4] # 并不是真的url all_task = [executor.submit(get_html, (url)) for url in urls] wait(all_task, return_when=ALL_COMPLETED) print("main")
标签:COMPLETED,times,sleep,import,print,线程,池中,ThreadPoolExecutor From: https://www.cnblogs.com/hushaojun/p/17400240.html