public class Test2 {
public static void main(String[] args) {
int [] arr={68,27,95,88,171,996,51,210};
int sum=getEvenNumberSum(arr);
System.out.println(sum);
}
/*
一个数组,元素是{68,27,95,88,171,996,51,210}
求出该数组中满足条件的元素和
要求:求和的元素个位,十位都不能是7,而且只能是偶数
*/
public static int getEvenNumberSum(int [] arr){
int sum=0;
for (int i = 0; i < arr.length; i++) {
int ge=arr[i]%10;
int shi=arr[i]/10%10;
if (ge!=7&&shi!=7&&arr[i]%2==0){
sum+=arr[i];
}
}
return sum;
}
}
标签:arr,210,求和,sum,累加,int,数组,public
From: https://blog.51cto.com/u_15988249/6215717