3.代码示例
#include<iostream>
using namespace std;
int main(){
int year,month,day,sum,s=0,i,q;
cin>>year>>month>>day;
int a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
if((year%4==0&&year%100!=0)||(year%400==0))
{
a[2]=29;
}
if((year-1990)%4<3){
sum=((year-1990)/4)*1461+(year-1990)%4*365;
}
else
{
sum=((year-1990)/4)*1461+(year-1990)%4*365+1;
}
for(i=1;i<month;i++){
s+=a[i];
}
q=sum+s+day;
if(q%5<4&&q%5>0)
cout<<"今天打鱼";
else
cout<<"今天晒网";
cout<<q;
return 0;
}
4.结果输出
标签：int,31,30,Day3,year,year% From： https://www.cnblogs.com/cream867/p/17320269.html