task1
#include <stdio.h> #include <stdlib.h> #include <time.h> #include <windows.h> #define N 80 void print_text(int line, int col, char text[]); void print_spaces(int n); void print_blank_lines(int n); int main() { int line, col, i; char text[N] = "hi, April~"; srand(time(0)); for(i = 1; i <= 10; ++i) { line = rand() % 25; col = rand() % 80; print_text(line, col, text); Sleep(1000); } return 0; } void print_spaces(int n) { int i; for(i = 1; i <= n; ++i) printf(" "); } void print_blank_lines(int n) { int i; for(i = 1; i <= n; ++i) printf("\n"); } void print_text(int line, int col, char text[]) { print_blank_lines(line-1); print_spaces(col-1); printf("%s", text); }
随机隔n个空白格和空白行打印"hi, April~"
task2.1
#include <stdio.h> long long fac(int n); int main(){ int i, n; printf("Enter n: "); scanf("%d", &n); for(i = 1; i <= n; ++i) printf("%d! = %lld\n", i, fac(i)); return 0; } long long fac(int n){ static long long p = 1; p = p * n; return p; }
#include <stdio.h> long long fac(int n); int main(){ int i, n; printf("Enter n: "); scanf("%d", &n); for(i = 1; i <= n; ++i) printf("%d! = %lld\n", i, fac(i)); return 0; } long long fac(int n){ static long long p = 1; p = p * n; printf("p = %lld\n", p); return p; }
task2.2
#include <stdio.h> int func(int, int); int main(){ int k = 4, m = 1, p1, p2; p1 = func(k, m); p2 = func(k, m); printf("%d, %d\n", p1, p2); return 0; } int func(int a, int b){ static int m = 0, i = 2; i += m + 1; m = i + a + b; return m; }
再次调用该函数,将保存上次的结果。
task3
#include <stdio.h> long long func(int n); int main() { int n; long long f; while (scanf("%d", &n) != EOF) { f = func(n); printf("n = %d, f = %lld\n", n, f); } return 0; } long long func(int n){ if(n == 1) return 1; else return 2 * func(n - 1) + 1; }
task4
#include <stdio.h> int func(int n, int m); int main(){ int n, m; while(scanf("%d%d", &n, &m) != EOF) printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m)); return 0; } int func(int n, int m){ if(m == 0 || m == n) return 1; if(m == 1) return n; if(n < m) return 0; if(m >1 && n > m) return func(n-1, m) + func(n-1, m-1); }
task5.1
#include <stdio.h> double mypow(int x, int y); int main() { int x, y; double ans; while (scanf("%d%d", &x, &y) != EOF) { ans = mypow(x, y); printf("%d的%d次方:%g\n\n", x, y, ans); } return 0; } double mypow(int x, int y){ double temp = 1.0; int i; if(y >= 0) for(i = 1; i <= y; i++){ temp = x * temp; } else for(i = 1; i <= -y; i++){ temp = temp / x; } return temp; }
task5.2
#include <stdio.h> double mypow(int x, int y); int main() { int x, y; double ans; while (scanf("%d%d", &x, &y) != EOF) { ans = mypow(x, y); printf("%d的%d次方:%g\n\n", x, y, ans); } return 0; } double mypow(int x, int y){ int i; if(y == 0) return 1; else if(y > 0) return mypow(x, y-1) * x; else return mypow(x, y+1) / x; }
task6
#include <stdio.h> #include <stdlib.h> void hanoi(unsigned int n, char from, char temp, char to); void moveplate(unsigned int n, char from, char to); int count; int main (){ unsigned int n; while(scanf("%u", &n) != EOF){ count = 0; hanoi(n, 'A', 'B', 'C'); printf("一共移动了%d次\n", count); } return 0; } void hanoi(unsigned int n, char from, char temp, char to) { if(n == 1) moveplate(n, from, to); else { hanoi(n-1, from, to, temp); moveplate(n, from, to); hanoi(n-1, temp, from, to); } } void moveplate(unsigned int n, char from, char to) { printf("%u: %c --> %c\n", n, from, to); count ++; }
task7
#include <stdio.h> #include <math.h> int is_prime(int n); int main() { int i, k, a[15], j = 0, l; for (k = 2; k <= 20; k++) { if (is_prime(k)) a[j++] = k; } for (i = 2; i <= 10; i++) { for (l = 1; l <= 10; l++) { if (is_prime(2 * i - a[l - 1])) { printf("%d = %d + %d\n", (2 * i), a[l - 1], (2 * i - a[l - 1])); break; } } } return 0; } int is_prime(int n) { int i, flag = 1; for (i = 2; i <= sqrt(n); i++) { if (n % i == 0) { flag = 0; break; } } return flag; }
task8
#include <stdio.h> #include <math.h> long func(long s); int main(){ long s, t; printf("Enter a number: "); while(scanf("%ld", &s) != EOF){ t = func(s); printf("new number is: %ld\n\n", t); printf("Enter a number: "); } return 0; } long func(long s){ long b=0,t=0; int a,m; while(s!=0){ a=s%10; if(a%2!=0) b=10*b+a; s=s/10; } while(b!=0){ m=b%10; t=10*t+m; b=b/10; } return t; }
标签:return,int,long,char,实验,func,include From: https://www.cnblogs.com/hr-0120/p/17273703.html