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实验三

时间:2023-03-31 11:56:39浏览次数:38  
标签:return int long 实验 func ans include

任务1:

代码:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <windows.h>
#define N 80

void print_text(int line,int col,char text[]);
void print_spaces(int n);
void print_blank_lines(int n);

int main(){
    int line,col,i;
    char text[N]="hi,April~";
    
    srand(time(0));
    
    for(i=1;i<=10;++i){
        line=rand()%25;
        col=rand()%80;
        print_text(line,col,text);
        Sleep(1000);
    }
    
    return 0;
 }
 
 void print_spaces(int n) {
    int i;
    
    for(i = 1; i <= n; ++i)
        printf(" ");
}

void print_blank_lines(int n) {
    int i;
    
    for(i = 1; i <= n; ++i)
        printf("\n");
 } 
 
void print_text(int line, int col, char text[]) {
    print_blank_lines(line-1);      
    print_spaces(col-1);            
    printf("%s", text);         
}

回答:每间隔1000ms,随机打印0~25个空白行和0~80个空白列再打印hi,April~。总共反复操作10次。

任务2:

代码1:

#include <stdio.h>
#include <stdio.h>
long long fac(int n);

int main() {
    int i, n;

    printf("Enter n: ");
    scanf("%d", &n);

    for (i = 1; i <= n; ++i)
        printf("%d! = %lld\n", i, fac(i));

    return 0;
}

long long fac(int n) {
    static long long p = 1;
    printf("p=%lld\n",p);
    p = p * n;

    return p;
}

截图

代码2:

#include <stdio.h>
int func(int, int);

int main() {
    int k = 4, m = 1, p1, p2;

    p1 = func(k, m);
    p2 = func(k, m);
    printf("%d, %d\n", p1, p2);

    return 0;
}

int func(int a, int b) {
    static int m = 0, i = 2;

    i += m + 1;
    m = i + a + b;

    return m;
}

截图

回答:static可以使局部变量在该函数结束时不会被系统回收空间,而是继续存在并保留原有值。

任务3:

代码:

#include <stdio.h>
long long func(int n);

int main() {
    int n;
    long long f;

    while (scanf("%d", &n) != EOF) {
        f = func(n);
        printf("n = %d, f = %lld\n", n, f);
    }

    return 0;
}

long long func(int n){
    long long f;
    if(n==1)
       f=1;
    else
       f=2*func(n-1)+1;
    return f;
}

截图

任务4:

代码:

#include <stdio.h>
int func(int n, int m);

int main() {
    int n, m;

    while(scanf("%d%d", &n, &m) != EOF)
        printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m));
    
    return 0;
}

int func(int n,int m){
    int C;
    if(m==0||m==n)
       C=1;
    else
        if(m>n)
          C=0;
        else
          C=func(n-1,m)+func(n-1,m-1);
    
    return C;
}

截图

任务5:

代码1:

#include <stdio.h>
double mypow(int x, int y);

int main() {
    int x, y;
    double ans;
    
    while(scanf("%d%d", &x, &y) != EOF) {
        ans = mypow(x, y);    
        printf("%d的%d次方: %g\n\n", x, y, ans);
    }
    return 0;
} 

double mypow(int x,int y){
    double ans=1;
    int i;
    if(y>=0)
        for(i=0;i<y;i++)
           ans=ans*x;
    else
        for(i=0;i>y;i--)
           ans=ans/x;
    
    return ans;
}

截图

代码2:

#include <stdio.h>
#include <math.h>
double mypow(int x, int y);

int main() {
    int x, y;
    double ans;
    
    while(scanf("%d%d", &x, &y) != EOF) {
        ans = mypow(x, y);    
        printf("%d的%d次方: %g\n\n", x, y, ans);
    }
    return 0;
} 

double mypow(int x,int y){
    double ans;
    if(y==0)
        ans=1;
    else
        ans=x*mypow(x,fabs(y)-1);
    if(y<0)
        ans=1/ans;    
    return ans;
}

截图

任务6:

代码:

#include <stdio.h>
#include <stdlib.h>
void hanio(unsigned int n,char from,char temp,char to);
void moveplate(unsigned int n,char from,char to);
int i;
int main(){
    unsigned int n;
    while(scanf("%u",&n)!=EOF){
        hanio(n,'A','B','C');
        printf("一共移动了%d次。\n",i);
        i=0;
    }
    return 0;
}
void hanio(unsigned int n,char from,char temp,char to){
    if(n==1)
        moveplate(n,from,to);
    else{
        hanio(n-1,from,to,temp);
        moveplate(n,from,to);
        hanio(n-1,temp,from,to);
    }
}
void moveplate(unsigned int n,char from,char to){
    printf("%u:%c-->%c\n",n,from,to);
    i++;
}

截图

任务7:

代码:

#include <stdio.h>
#include <math.h>
int is_prime(double n);
int sovle(int ans);
int main(){
    int n,ans;
    while(scanf("%d",&ans)!=EOF){
        n=sovle(ans);
        printf("%d=%d+%d\n",ans,ans-n,n);
    }
    return 0;
} 
int sovle(int ans){
    double n=ans-2.0;
    while(is_prime(n)==0||is_prime(ans-n)==0){
        n--;
    }
    return (int)n;
}
int is_prime(double n){
    int m;
    for(m=2;;m++){
        if(m>sqrt(n))
            return 1;
        else
            if((int)n%m==0)
                return 0;
    }
}

截图

任务8:

代码:

#include <stdio.h>
#include <math.h>
long func(long s);
int main(){
    long s,t;
    printf("Enter a number:");
    while(scanf("%ld",&s)!=EOF){
        t=func(s);
        printf("new number is:%ld\n\n",t);
        printf("Enter a number:");
    }
    return 0;
}
long func(long s){
    int t=0;
    double i;
    while(s!=0){
        if(s%10%2==1)
            t=t+s%10*pow(10.0,i),i++;
        s=s/10;
    }
    return t;
}

截图

 

标签:return,int,long,实验,func,ans,include
From: https://www.cnblogs.com/FC000/p/17273740.html

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