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leetcode-1450-easy

时间:2023-03-24 20:12:53浏览次数:44  
标签:easy doing queryTime 1450 startTime time endTime leetcode homework

Number of Students Doing Homework at Given Time

Given two integer arrays startTime and endTime and given an integer queryTime.

The ith student started doing their homework at the time startTime[i] and finished it at time endTime[i].

Return the number of students doing their homework at time queryTime. More formally, return the number of students where queryTime lays in the interval [startTime[i], endTime[i]] inclusive.

Example 1:

Input: startTime = [1,2,3], endTime = [3,2,7], queryTime = 4
Output: 1
Explanation: We have 3 students where:
The first student started doing homework at time 1 and finished at time 3 and wasn't doing anything at time 4.
The second student started doing homework at time 2 and finished at time 2 and also wasn't doing anything at time 4.
The third student started doing homework at time 3 and finished at time 7 and was the only student doing homework at time 4.
Example 2:

Input: startTime = [4], endTime = [4], queryTime = 4
Output: 1
Explanation: The only student was doing their homework at the queryTime.
Constraints:

startTime.length == endTime.length
1 <= startTime.length <= 100
1 <= startTime[i] <= endTime[i] <= 1000
1 <= queryTime <= 1000

思路一:直接遍历

    public int busyStudent(int[] startTime, int[] endTime, int queryTime) {
        int count = 0;
        for (int i = 0; i < startTime.length; i++) {
            if (startTime[i] <= queryTime && endTime[i] >= queryTime) {
                count++;
            }
        }
        return count;
    }

标签:easy,doing,queryTime,1450,startTime,time,endTime,leetcode,homework
From: https://www.cnblogs.com/iyiluo/p/17253189.html

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