pat 乙级1031 查验身份证

 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 #include <string.h>
 4 #include <math.h>
 5 
 6 int main()
 7 {
 8     int n;
 9     scanf("%d", &n);
10     char id[n][19];
11     int num[17] = {7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2};
12     char num2[11] = {'1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'};
13     int i = 0, j = 0;
14     int count = 0;
15     for (i = 0; i < n; i++)
16     {
17         scanf("%s", id[i]);
18     }
19     int sum = 0;
20     int flag = 1;
21     int flag2 = 1;
22     for (i = 0; i < n; i++)
23     {
24         flag = 1;
25         sum = 0;
26         for (j = 0; j < 17; j++)
27         {
28             if (id[i][j] >= '0' && id[i][j] <= '9')
29             {
30                 sum = sum + (id[i][j] - '0') * num[j];
31             }
32             else
33             {
34                 flag = 0;
35                 break;
36             }
37         }
38         if (num2[sum % 11] == id[i][17] && flag == 1)
39         {
40             count++;
41             continue;
42         }
43         if (flag2 == 1)
44         {
45             printf("%s", id[i]);
46             
47         }
48         if (flag2 == 0)
49         {
50             printf("\n%s", id[i]);
51         }
52         flag2 = 0;
53     }
54     if (count == n)
55     {
56         printf("All passed");
57     }
58     return 0;
59 }