- 无语,就是两个栈倒来倒去
class MyQueue {
public:
stack<int> st;
stack<int> tmp;
/** Initialize your data structure here. */
MyQueue() {
}
/** Push element x to the back of queue. */
void push(int x) {
st.push(x);
}
/** Removes the element from in front of queue and returns that element. */
int pop() {
int res;
while(st.size())
{
res=st.top();
tmp.push(res);
st.pop();
}
int t;
tmp.pop();
while(tmp.size())
{
t=tmp.top();
st.push(t);
tmp.pop();
}
return res;
}
/** Get the front element. */
int peek() {
int res;
while(st.size())
{
res=st.top();
tmp.push(res);
st.pop();
}
int t;
while(tmp.size())
{
t=tmp.top();
st.push(t);
tmp.pop();
}
return res;
}
/** Returns whether the queue is empty. */
bool empty() {
return !st.size();
}
};
/**
* Your MyQueue object will be instantiated and called as such:
* MyQueue obj = MyQueue();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.peek();
* bool param_4 = obj.empty();
*/
标签:tmp,两个,队列,res,pop,st,实现,int,push
From: https://www.cnblogs.com/tangxibomb/p/17215143.html