计算（2+22+222······）类似的式子

int main()
{
  int p = 0;//设的数字
  int i = 0;
  int z = 0;
  int d = 0;//自定义前几项
  int r = 0;//一项
  scanf("%d %d", &p,&d);
  for (i = 0; i < d; i++)
  {
    r = r * 10 + p;//先算出一项来
    z = z + r;//算总和
  }
  printf("Sn==%d\n", z);
  return 0;
}