题目
约束
题解
方法一
class Solution {
public:
int numTrees(int n) {
vector<int> G(n + 1, 0);
G[0] = 1;
G[1] = 1;
for (int i = 2; i <= n; ++i) {//长度
for (int j = 1; j <= i; ++j) {//节点
G[i] += G[j - 1] * G[i - j];
}
}
return G[n];
}
};
标签:int,题解,二叉,搜索,LeetCode,96
From: https://www.cnblogs.com/chuixulvcao/p/17181266.html