Shuffle String
You are given a string s and an integer array indices of the same length. The string s will be shuffled such that
the character at the ith position moves to indices[i] in the shuffled string.
Return the shuffled string.
Example 1:
Input: s = "codeleet", indices = [4,5,6,7,0,2,1,3]
Output: "leetcode"
Explanation: As shown, "codeleet" becomes "leetcode" after shuffling.
Example 2:
Input: s = "abc", indices = [0,1,2]
Output: "abc"
Explanation: After shuffling, each character remains in its position.
Constraints:
s.length == indices.length == n
1 <= n <= 100
s consists of only lowercase English letters.
0 <= indices[i] < n
All values of indices are unique.
思路一:直接遍历
public String restoreString(String s, int[] indices) {
char[] chars = s.toCharArray();
char[] result = new char[chars.length];
for (int i = 0; i < indices.length; i++) {
result[indices[i]] = chars[i];
}
return new String(result);
}
标签:String,char,length,easy,indices,1528,leetcode,string
From: https://www.cnblogs.com/iyiluo/p/17178068.html