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LG P5244 [USACO19FEB] Mowing Mischief P

时间:2023-02-23 21:33:07浏览次数:44  
标签:LG ch Mischief cur int void mid P5244 return

\(\text{Code}\)

#include <bits/stdc++.h> 
#define IN inline
#define eb emplace_back
using namespace std;

template<typename Tp>
IN void read(Tp &x) {
    x = 0; char ch = getchar(); int f = 0;
    for(; !isdigit(ch); f |= (ch == '-'), ch = getchar());
    for(; isdigit(ch); x = (x<<3)+(x<<1)+(ch^48), ch = getchar());
    if (f) x = ~x + 1;
}

typedef long long LL;
const int N = 2e5 + 5, M = 1e6 + 5;
const LL INF = 1e18;
struct point{int x, y;}a[N];
int lis[N], n, m;
LL f[N], g[N];
vector<int> G[N];

IN LL calc(int x1, int y1, int x0, int y0){return (LL)(x1 - x0) * (y1 - y0);}

struct SegmentTree {
    #define ls (p << 1)
    #define rs (ls | 1)
    vector<int> Q[N << 2];
    
    void build(int p, int l, int r) {
        Q[p].clear(); if (l == r) return;
        int mid = l + r >> 1; build(ls, l, mid), build(rs, mid + 1, r);
    }
    void insert(int p, int l, int r, int x, int y, int z) {
        if (x > r || y < l) return;
        if (x <= l && r <= y) return Q[p].eb(z), void();
        int mid = l + r >> 1;
        insert(ls, l, mid, x, y, z), insert(rs, mid + 1, r, x, y, z);
    }
    
    void solve(int p, int l, int r, int L, int R, int cur) {
        if (r < l || R < L) return;
        int mid = l + r >> 1, bst = 0;
        for(int i = L; i <= R; i++) {
            LL s = f[G[cur - 1][i]] + calc(a[Q[p][mid]].x, a[Q[p][mid]].y, a[G[cur - 1][i]].x, a[G[cur - 1][i]].y);
            if (g[Q[p][mid]] > s) g[Q[p][mid]] = s, bst = i;
        }
        solve(p, l, mid - 1, bst, R, cur), solve(p, mid + 1, r, L, bst, cur);
    }
    void dfs(int p, int l, int r, int cur) {
        for(auto v : Q[p]) g[v] = INF;
        solve(p, 0, Q[p].size() - 1, l, r, cur);
        for(auto v : Q[p]) f[v] = min(f[v], g[v]);
        if (l == r) return; int mid = l + r >> 1;
        dfs(ls, l, mid, cur), dfs(rs, mid + 1, r, cur);
    }
}T;

struct BIT {
    int c[M];
    IN int lowbit(int x){return x & -x;}
    IN void add(int x, int v){for(; x <= m; x += lowbit(x)) c[x] = max(c[x], v);}
    IN int query(int x){int s = 0; for(; x; x -= lowbit(x)) s = max(c[x], s); return s;}
}bit;

IN void solve() {
    for(int i = 1; i <= n; i++) lis[i] = bit.query(a[i].y) + 1, bit.add(a[i].y, lis[i]);
    for(int i = 0; i <= n; i++) G[lis[i]].eb(i);
    for(int i = 1; i <= n; i++) sort(G[i].begin(), G[i].end(), [](int x, int y){return a[x].x < a[y].x;});
    for(int i = 1; i <= n; i++) f[i] = INF;
    for(int i = 1; i <= n && G[i].size(); i++) {
        T.build(1, 0, G[i - 1].size() - 1);
        int p = 0, q = 0;
        for(auto j : G[i]) {
            while (p < G[i - 1].size() && a[G[i - 1][p]].x <= a[j].x) ++p;
            while (q < G[i - 1].size() && a[G[i - 1][q]].y > a[j].y) ++q;
            T.insert(1, 0, G[i - 1].size() - 1, q, p - 1, j);
        }
        T.dfs(1, 0, G[i - 1].size() - 1, i);
    }
}

int main() {
    freopen("mowing.in", "r", stdin);
    freopen("mowing.out", "w", stdout);
    read(n), read(m);
    for(int i = 1; i <= n; i++) read(a[i].x), read(a[i].y);
    sort(a + 1, a + n + 1, [](point a, point b){return a.x < b.x;});
    solve();
    int mx = 0;
    for(int i = 1; i <= n; i++) mx = max(mx, lis[i]);
    LL ans = INF;
    for(int i = 1; i <= n; i++) if (lis[i] == mx) ans = min(ans, f[i] + calc(m, m, a[i].x, a[i].y));
    printf("%lld\n", ans);
}

标签:LG,ch,Mischief,cur,int,void,mid,P5244,return
From: https://www.cnblogs.com/leiyuanze/p/17149526.html

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