- 找出字符串中第一个匹配项的下标
class Solution {
public:
int strStr(string haystack, string needle) {
if (needle.size() == 0) return 0;
vector<int> next(needle.size());
getNext(next, needle);
int j = -1;
for (int i = 0; i < haystack.size(); i++) {
while(j >= 0 && haystack[i] != needle[j+1]) {
j = next[j];
}
if (haystack[i] == needle[j+1]) {
j++;
}
if (j == (needle.size() - 1)) {
return (i - needle.size() + 1);
}
}
return -1;
}
void getNext(vector<int> & next, const string &s) {
int j = -1;
next[0] = j;
for(int i = 1; i < s.size(); i++) {
while (j >= 0 && s[i] != s[j + 1]) {
j = next[j];
}
if (s[i] == s[j+1]) {
j++;
}
next[i] = j;
}
}
};
- 重复的子字符串
class Solution {
public:
bool repeatedSubstringPattern(string s) {
return (s + s).find(s, 1) != s.size();
}
};
标签:459,return,--,needle,next,int,字符串,size
From: https://www.cnblogs.com/zjacky/p/17142317.html