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HDOJ2131 Probability

时间:2023-02-20 10:37:01浏览次数:32  
标签:cha chb word Probability probability HDOJ2131 letter scanner


Probability


Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 8311    Accepted Submission(s): 4017


Problem Description


Mickey is interested in probability recently. One day , he played a game which is about probability with mini.First mickey gives a letter and a word to mini.Then mini calculate the probability that the letter appears in the word.For example,give you the letter "a" and the word "apple". the probability of this case is 0.20000.


 



Input


The input contains several test cases. Each test case consists of a letter and a word.The length of the word is no longer than 200.


 



Output


For each test case, print the probability rounded to five digits after the decimal point.


 



Sample Input


a apple c Candy a banana


 



Sample Output


0.20000 0.20000 0.50000


import java.util.Scanner;

public class Main{
private static Scanner scanner;

public static void main(String[] args) {
scanner = new Scanner(System.in);
while (scanner.hasNext()) {
String a = scanner.next();
String b = scanner.next();
char cha = a.charAt(0);
char chb[] = b.toCharArray();
int count = 0;
for (int i = 0; i < chb.length; i++) {
//A65 a97
if (chb[i] == cha || chb[i] == cha + 32 || chb[i] == cha - 32) {
count++;
}
}
double prob = 1.0 * count / chb.length;
System.out.printf("%.5f", prob);
System.out.println();
}
}
}


标签:cha,chb,word,Probability,probability,HDOJ2131,letter,scanner
From: https://blog.51cto.com/u_15741949/6067722

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