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leetcode-1374-easy

时间:2023-02-15 21:35:30浏览次数:44  
标签:string strings valid result easy Input such leetcode 1374

Generate a String With Characters That Have Odd Counts

Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times.

The returned string must contain only lowercase English letters. If there are multiples valid strings, return any of them.

Example 1:

Input: n = 4
Output: "pppz"
Explanation: "pppz" is a valid string since the character 'p' occurs three times and the character 'z' occurs once. Note that there are many other valid strings such as "ohhh" and "love".
Example 2:

Input: n = 2
Output: "xy"
Explanation: "xy" is a valid string since the characters 'x' and 'y' occur once. Note that there are many other valid strings such as "ag" and "ur".
Example 3:

Input: n = 7
Output: "holasss"
Constraints:

1 <= n <= 500

思路一:判断奇偶数

public String generateTheString(int n) {
StringBuilder result = new StringBuilder();

        boolean isOdd = (n & 1) == 1;

        for (int i = 0; i < (isOdd ? n : n - 1); i++) {
            result.append('a');
        }

        if (!isOdd) {
            result.append('b');
        }

        return result.toString();
    }

标签:string,strings,valid,result,easy,Input,such,leetcode,1374
From: https://www.cnblogs.com/iyiluo/p/17124761.html

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